Ratio, Proportion and Rates of Change

KS3

MA-KS3-D006

Understanding and applying ratio, proportion, percentage change, direct and inverse proportion, and compound units

National Curriculum context

Ratio, proportion and rates of change at KS3 formalise the multiplicative reasoning developed informally in primary school into precise mathematical tools used across mathematics and other subjects. Pupils learn to express and use ratios, scale factors, fractions and percentages interchangeably, and to solve problems involving direct and inverse proportion. The curriculum introduces rates of change in contexts such as speed, unit pricing and gradient — connecting proportion to the concept of linearity that underpins much of algebra and science. This domain also includes formal work with percentage change, compound measures and the mathematics of similarity and scale, all of which have direct applications in real-world quantitative contexts.

13

Concepts

4

Clusters

6

Prerequisites

13

With difficulty levels

AI Direct: 12
AI Facilitated: 1

Lesson Clusters

1

Understand ratio notation, divide in a ratio and link to fractions

introduction Curated

Ratio notation, dividing in a ratio, expressing as a fraction and the link between ratios and fractions are mutually co-taught (C050 lists C049, C051; C049 lists C050, C052, C053). This cluster establishes the conceptual foundation.

4 concepts Scale, Proportion and Quantity
2

Apply scale factors, percentage change and financial mathematics

practice Curated

Scale factors/diagrams, percentage change and financial mathematics are applied ratio and proportion contexts. C048 co-teaches with C053, C057; C054 is standalone with high practical relevance alongside financial contexts.

3 concepts Scale, Proportion and Quantity
3

Solve problems involving direct and inverse proportion and multiplicative reasoning

practice Curated

Multiplicative relationships, direct proportion, inverse proportion and additive vs multiplicative reasoning are linked (C056 co-teaches with C055, C052, C094; C094 lists C055, C056). This is the proportional reasoning cluster.

4 concepts Scale, Proportion and Quantity
4

Convert between units and use compound units in problem-solving

practice Curated

Unit conversion and compound units (speed, density, pressure) are co-taught (C047 co-teaches with C057; C057 extensively cross-references). These form the measurement application within the ratio domain.

2 concepts Scale, Proportion and Quantity

Prerequisites

Concepts from other domains that pupils should know before this domain.

Concepts (13)

Unit conversion

skill AI Direct

MA-KS3-C047

Converting between related standard units (time, length, area, volume, mass)

Teaching guidance

Teach conversion as multiplication or division by powers of 10, using a conversion staircase or table showing the relationships between units. For length: mm → cm → m → km with factors of 10, 100 and 1000. Extend to area units (1 m² = 10,000 cm²) and volume units (1 m³ = 1,000,000 cm³) by reasoning about the number of dimensions. Include time conversions (which are not base-10) and conversions between metric and common imperial units. Use dimensional analysis for compound units.

Vocabulary: convert, unit, metric, imperial, length, mass, capacity, volume, area, milli-, centi-, kilo-, prefix, equivalence, dimension
Common misconceptions

Pupils commonly multiply when they should divide (or vice versa) — particularly converting from smaller to larger units. Area and volume conversions cause more difficulty because pupils apply linear conversion factors instead of squaring or cubing them (e.g., thinking 1 m² = 100 cm² instead of 10,000 cm²). Time conversions are error-prone because they are not base-10.

Difficulty levels

Emerging

Can convert between basic metric units (e.g. cm to m, g to kg) using simple multiplication or division by 10, 100, 1000.

Example task

Convert 3.5 km to metres.

Model response: 1 km = 1000 m, so 3.5 km = 3.5 × 1000 = 3500 m.

Developing

Converts between a range of metric units including area and volume units, understanding why area units use squared conversion factors.

Example task

Convert 2.4 m² to cm².

Model response: 1 m = 100 cm, so 1 m² = 100 × 100 = 10,000 cm². Therefore 2.4 m² = 2.4 × 10,000 = 24,000 cm².

Secure

Converts fluently between all standard units including time, area, volume and compound units, choosing the most efficient method.

Example task

Convert 72 km/h to m/s.

Model response: 72 km/h = 72,000 m / 3600 s = 20 m/s. Shortcut: divide by 3.6 (since 1 m/s = 3.6 km/h). 72 ÷ 3.6 = 20 m/s.

Mastery

Solves problems requiring multi-step unit conversions and understands dimensional analysis as a systematic approach.

Example task

A tap fills a container at 0.5 litres per second. How many cubic centimetres per minute is this?

Model response: 0.5 L/s = 500 cm³/s (since 1 L = 1000 cm³). Per minute: 500 × 60 = 30,000 cm³/min. Using dimensional analysis: 0.5 L/s × 1000 cm³/L × 60 s/min = 30,000 cm³/min.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Scale factors and diagrams

skill AI Direct

MA-KS3-C048

Using scale factors, scale diagrams and maps to represent real situations

Teaching guidance

Use maps and architectural plans as concrete starting points: measure distances on the map and use the scale to find real distances. Introduce scale factor as a multiplier — a scale of 1:50000 means every 1 cm on the map represents 50000 cm (500 m) in reality. Progress to using scale factors to enlarge and reduce shapes. Practise creating scale drawings with a given scale factor. Connect to ratio work: a scale of 1:5 is the same as the ratio 1:5. Include contexts where pupils must choose an appropriate scale for a drawing.

Vocabulary: scale, scale factor, scale drawing, map scale, ratio, enlarge, reduce, proportion, representative fraction, actual size, model
Common misconceptions

Pupils often confuse which way the scale factor works — multiplying by the scale factor to go from real to model instead of the reverse. When a map scale is given as 1:50000, pupils may not convert between centimetres on the map and metres or kilometres in reality. Some pupils apply the scale factor to areas without squaring it, or to volumes without cubing it.

Difficulty levels

Emerging

Understands what a scale means and can use a simple scale to find real distances from a map.

Example task

On a map, 1 cm represents 5 km. Two towns are 3.5 cm apart. What is the real distance?

Model response: 3.5 × 5 = 17.5 km.

Developing

Uses scale factors to create or interpret scale drawings, converting between real and scaled measurements in both directions.

Example task

A room is 6 m by 4.5 m. Draw a scale diagram using a scale of 1:100.

Model response: Scale 1:100 means 1 cm represents 100 cm = 1 m. So the drawing is 6 cm by 4.5 cm.

Secure

Applies scale factors to areas and volumes, understanding that area scales by k² and volume by k³.

Example task

A model car is built at scale 1:20. The real car is 4 m long and has a windscreen area of 1.2 m². Find the model's length and windscreen area.

Model response: Length: 4 m ÷ 20 = 0.2 m = 20 cm. Area: 1.2 ÷ 20² = 1.2 ÷ 400 = 0.003 m² = 30 cm².

Mastery

Solves complex real-world problems involving scale, including those requiring scale conversion between different representations and critical evaluation of scale accuracy.

Example task

Two maps show the same region. Map A has scale 1:50,000 and Map B has scale 1:25,000. A distance is 6 cm on Map A. How long is it on Map B?

Model response: Real distance = 6 × 50,000 = 300,000 cm = 3 km. On Map B: 300,000 ÷ 25,000 = 12 cm. Alternatively: Map B is at twice the scale of Map A, so distances are doubled: 6 × 2 = 12 cm.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Expressing as a fraction

skill AI Direct

MA-KS3-C049

Expressing one quantity as a fraction of another (proper and improper fractions)

Teaching guidance

Use bar models and fraction walls to visualise one quantity as a fraction of another. Start with straightforward examples: 'What fraction of 20 is 5?' (5/20 = ¼). Progress to improper fractions: 'Express 30 as a fraction of 20' (30/20 = 3/2). Connect to ratio — expressing one quantity as a fraction of another is closely related to finding the ratio between them. Include decimal and contextual examples: 'A 750 ml bottle is what fraction of a 2-litre bottle?' Connect to percentage work: expressing as a fraction is the first step towards expressing as a percentage.

Vocabulary: fraction of, express, proper fraction, improper fraction, part, whole, compare, ratio, proportion, numerator, denominator
Common misconceptions

Pupils often put the quantities the wrong way round — dividing the whole by the part instead of the part by the whole. When the answer is an improper fraction, pupils may think they have made an error because 'fractions should be less than 1'. Some pupils do not simplify their answers, leaving fractions in non-simplified form.

Difficulty levels

Emerging

Can express one quantity as a fraction of another when the context is straightforward.

Example task

There are 8 red balls and 20 balls in total. What fraction are red?

Model response: 8/20 = 2/5 are red.

Developing

Expresses quantities as fractions including improper fractions, and simplifies using HCF.

Example task

Express 45 minutes as a fraction of 2 hours.

Model response: 2 hours = 120 minutes. 45/120 = 9/24 = 3/8.

Secure

Uses fraction-of to solve comparison and proportion problems, including connecting to percentage and ratio representations.

Example task

A school has 600 pupils. 240 study French, 180 study Spanish, and the rest study German. Express each as a fraction and a percentage.

Model response: French: 240/600 = 2/5 = 40%. Spanish: 180/600 = 3/10 = 30%. German: 180/600 = 3/10 = 30%.

Mastery

Applies fractional reasoning to complex multi-step problems and understands the algebra of proportional relationships.

Example task

In a jar, 2/5 of the sweets are red and 1/3 of the remainder are blue. What fraction are blue?

Model response: Red = 2/5. Remainder = 1 - 2/5 = 3/5. Blue = 1/3 of 3/5 = 1/5. So 1/5 of all sweets are blue.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Ratio notation

knowledge AI Direct

MA-KS3-C050

Using ratio notation (a:b) and simplifying ratios to simplest form

Teaching guidance

Introduce ratio through practical sharing activities: 'Share 20 counters between two people in the ratio 3:2.' Use bar models as the primary representation — each part of the ratio corresponds to one bar, and the total is divided into equal parts. Teach simplifying ratios using HCF, connecting to fraction simplification. Practise converting between ratio forms (part:part and part:whole) and between ratios and fractions. Include contexts: recipes, mixing paint colours, map scales. Emphasise that a ratio shows a multiplicative relationship, not additive.

Vocabulary: ratio, ratio notation, simplify, simplest form, part, share, divide, proportion, equivalent ratio, unitary ratio, colon
Common misconceptions

Pupils often treat ratio as additive — thinking that increasing a 2:3 recipe by 4 means adding 4 to each part (giving 6:7) rather than multiplying (giving 8:12). Some pupils confuse ratio and fraction, thinking 2:3 means ⅔ of the total rather than ⅖. When simplifying ratios, pupils may divide the parts by different numbers. Mixing up part:part and part:whole ratios is also very common.

Difficulty levels

Emerging

Understands that a ratio compares two or more quantities and can write a ratio from a description.

Example task

In a class of 30, there are 18 girls and 12 boys. Write the ratio of girls to boys.

Model response: Girls to boys = 18:12 = 3:2.

Developing

Simplifies ratios by dividing by common factors and converts between ratio and fraction forms.

Example task

Simplify the ratio 45:60:75.

Model response: Divide all parts by 15: 45:60:75 = 3:4:5.

Secure

Solves problems using ratio, converting between ratio, fraction and percentage representations as needed.

Example task

Purple paint is made by mixing red and blue in the ratio 3:5. How much blue is needed to mix with 12 litres of red?

Model response: Red:Blue = 3:5. If red = 12 litres, the scale factor is 12/3 = 4. Blue = 5 × 4 = 20 litres.

Mastery

Solves complex ratio problems involving changing ratios, combining ratios, and algebraic ratio reasoning.

Example task

The ratio of cats to dogs in a shelter is 3:5. After 6 more cats arrive, the ratio becomes 3:4. How many animals were there originally?

Model response: Originally: cats = 3k, dogs = 5k. After: cats = 3k + 6, dogs = 5k. New ratio: (3k+6)/5k = 3/4. Cross-multiply: 4(3k+6) = 3(5k). 12k + 24 = 15k. 24 = 3k. k = 8. Originally: 3(8) + 5(8) = 24 + 40 = 64 animals.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Dividing in a ratio

skill AI Direct

MA-KS3-C051

Dividing quantities in given part:part or part:whole ratios

Teaching guidance

Use bar models to represent the total quantity divided into parts according to the ratio. For part:part ratios, find the total number of parts first, then find the value of one part (total ÷ number of parts), then multiply to find each share. For part:whole ratios, the 'whole' bar is one of the given parts. Present multi-step problems: 'Orange squash is mixed in the ratio 1:4 concentrate to water. How much concentrate is needed for 2 litres of squash?' Progress to three-part ratios. Emphasise the unitary method — finding the value of one part first.

Vocabulary: divide in a ratio, share, part, whole, unitary method, total parts, proportion, part:part ratio, part:whole ratio, allocate
Common misconceptions

Pupils often divide the quantity by the ratio numbers directly (e.g., dividing £60 in ratio 2:3 as £60 ÷ 2 = £30 and £60 ÷ 3 = £20, giving £50 not £60). Some pupils add the ratio parts incorrectly. Others confuse part:part with part:whole — if told '¾ are girls', they may set up a ratio of 3:4 (girls:total) instead of 3:1 (girls:boys).

Difficulty levels

Emerging

Can share a quantity into a given ratio when the number of parts is small.

Example task

Share £20 in the ratio 1:3.

Model response: Total parts = 1 + 3 = 4. Each part = £20 ÷ 4 = £5. First share: 1 × £5 = £5. Second share: 3 × £5 = £15.

Developing

Divides quantities in ratios with two or three parts, checking the answers add to the original amount.

Example task

Divide 360° in the ratio 2:3:4.

Model response: Total parts = 2+3+4 = 9. Each part = 360 ÷ 9 = 40°. Shares: 80°, 120°, 160°. Check: 80+120+160 = 360° ✓.

Secure

Solves ratio division problems in context, including finding one share when another is known.

Example task

Amit and Beth share money in the ratio 5:3. Amit gets £30 more than Beth. How much does each get?

Model response: Difference in parts: 5 - 3 = 2 parts = £30. So 1 part = £15. Amit: 5 × £15 = £75. Beth: 3 × £15 = £45. Check: £75 - £45 = £30 ✓.

Mastery

Solves problems involving changing ratios and multi-step ratio reasoning.

Example task

A drink is made from juice and water in the ratio 2:5. 200 ml of water is added to 350 ml of drink. What is the new ratio of juice to water?

Model response: Original 350 ml in ratio 2:5: juice = 2/7 × 350 = 100 ml, water = 5/7 × 350 = 250 ml. After adding 200 ml water: juice = 100 ml, water = 250 + 200 = 450 ml. New ratio = 100:450 = 2:9.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Multiplicative relationships

knowledge AI Direct

MA-KS3-C052

Understanding that multiplicative relationships can be expressed as ratios or fractions

Teaching guidance

Contrast additive and multiplicative relationships using side-by-side examples: 'If I add 3 to the length, I add 3 to the width' (additive) versus 'If I double the length, I double the width' (multiplicative). Show that multiplicative relationships can be expressed as ratios (the ratio stays constant) or as fractions (one quantity is always the same fraction of the other). Use double number lines and ratio tables to represent these relationships. Connect to direct proportion — when two quantities have a constant multiplicative relationship, they are directly proportional.

Vocabulary: multiplicative relationship, ratio, fraction, scale factor, constant, proportional, additive, multiplier, equivalence, double number line
Common misconceptions

The fundamental misconception is applying additive reasoning to multiplicative situations. For example, when told that 3 pencils cost 45p, pupils may calculate 5 pencils as 45p + 30p = 75p (adding 2 × 15p) rather than 5 × 15p = 75p. Some pupils cannot distinguish between situations requiring additive versus multiplicative reasoning without explicit scaffolding.

Difficulty levels

Emerging

Recognises that doubling one quantity and doubling the other keeps the same relationship — an early sense of multiplicative reasoning.

Example task

If 3 apples cost 90p, how much do 6 apples cost?

Model response: 6 is double 3, so the cost is double 90p = 180p = £1.80.

Developing

Understands that ratios express multiplicative relationships and can use this to solve proportion problems.

Example task

If 5 notebooks cost £4, how much do 8 notebooks cost?

Model response: Cost per notebook = £4 ÷ 5 = £0.80. Cost of 8 = 8 × £0.80 = £6.40.

Secure

Identifies and uses multiplicative relationships in ratio, fraction and algebraic contexts, distinguishing from additive relationships.

Example task

y is proportional to x. When x = 4, y = 10. Find y when x = 14.

Model response: y/x = 10/4 = 2.5 (constant multiplier). When x = 14: y = 14 × 2.5 = 35.

Mastery

Distinguishes between additive, multiplicative, and other functional relationships, applying the correct reasoning in each case.

Example task

Alice says: 'If I add 3 to x and also add 3 to y, the ratio stays the same.' Is Alice correct? Test with the ratio 2:5.

Model response: Original ratio 2:5. Adding 3: 5:8. Is 5/8 = 2/5? 5/8 = 0.625, 2/5 = 0.4. No — the ratio has changed. Adding the same number to both parts of a ratio changes the ratio (this is additive reasoning, but ratios require multiplicative reasoning). To keep ratio 2:5, you must multiply both by the same factor: e.g. 4:10, 6:15, etc.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Ratios and fractions link

knowledge AI Direct

MA-KS3-C053

Relating ratio language and calculations to fraction arithmetic and linear functions

Teaching guidance

Use concrete examples to show the same relationship expressed as a ratio and as a fraction: 'The ratio of blue to red counters is 2:3' means '⅖ of the counters are blue and ⅗ are red'. Use conversion exercises where pupils move between the representations. Show that the relationship can also be expressed as a linear function: if b:r = 2:3, then b = ⅔r. Plot this function on a graph to show the proportional relationship visually. Include percentage conversions as a third representation of the same relationship.

Vocabulary: ratio, fraction, proportion, linear function, equivalent, convert, relationship, part, whole, graph, gradient, direct proportion
Common misconceptions

Pupils often struggle to convert between ratio and fraction because they confuse part:part ratio with part:whole fraction. For a ratio 2:3, pupils may write the fraction as ⅔ (which gives the relationship between the parts) rather than ⅖ or ⅗ (which give the part-to-whole fractions). The connection to linear functions is new and abstract — pupils may not see why y = ⅔x represents the same relationship as 2:3.

Difficulty levels

Emerging

Can see that a ratio of 1:4 means one part out of five total, connecting to a simple fraction.

Example task

In a ratio of 1:4, what fraction is the smaller part?

Model response: Total parts = 1 + 4 = 5. The smaller part is 1/5.

Developing

Converts between ratio and fraction notation and uses both to solve problems.

Example task

Red paint and white paint are mixed in the ratio 2:3. What fraction of the mixture is red?

Model response: Total = 2 + 3 = 5 parts. Red fraction = 2/5.

Secure

Connects ratio, fraction and linear function representations, seeing a:b as equivalent to the function y = (a/b)x.

Example task

The ratio of boys to girls is 3:5. If there are 40 girls, write a formula connecting boys (b) and girls (g).

Model response: b/g = 3/5, so b = (3/5)g. When g = 40: b = (3/5)(40) = 24 boys.

Mastery

Uses the connections between ratio, fraction and linear functions to solve complex problems and prove general results.

Example task

If a:b = 3:4 and b:c = 2:5, find a:b:c.

Model response: Make the b values equal. a:b = 3:4 and b:c = 2:5. LCM of 4 and 2 is 4. Scale second ratio: b:c = 4:10. Now a:b:c = 3:4:10. Check: a:b = 3:4 ✓, b:c = 4:10 = 2:5 ✓.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Percentage change

skill AI Direct

MA-KS3-C054

Solving problems with percentage increase, decrease, original value and simple interest

Teaching guidance

Teach percentage increase and decrease using the multiplier method: a 15% increase means multiplying by 1.15, a 15% decrease means multiplying by 0.85. Use bar models to show why: the original amount is 100%, so increasing by 15% gives 115% = 1.15. For reverse percentage problems ('After a 20% discount, the price is £48. What was the original price?'), emphasise that £48 represents 80% of the original, so the original is £48 ÷ 0.80. Include simple interest calculations in financial contexts.

Vocabulary: percentage increase, percentage decrease, multiplier, original value, reverse percentage, simple interest, profit, loss, discount, VAT, appreciation, depreciation
Common misconceptions

The most common error in reverse percentage problems is adding/subtracting the percentage from the new amount — for example, if a price after a 20% increase is £60, pupils calculate the original as £60 - 20% of £60 = £48, rather than £60 ÷ 1.20 = £50. Pupils also frequently confuse percentage increase with finding a percentage of a quantity.

Difficulty levels

Emerging

Can calculate a simple percentage increase or decrease given the percentage and the original amount.

Example task

A shirt costs £40. It is reduced by 20%. What is the sale price?

Model response: 20% of £40 = £8. Sale price = £40 - £8 = £32.

Developing

Uses multipliers for percentage change (1.15 for a 15% increase, 0.85 for a 15% decrease) for efficiency.

Example task

Increase £250 by 12%.

Model response: Multiplier = 1.12. New amount = 250 × 1.12 = £280.

Secure

Finds the original value before a percentage change (reverse percentage) and solves simple interest problems.

Example task

After a 15% increase, a price is £69. Find the original price.

Model response: £69 = 115% of original. Original = £69 ÷ 1.15 = £60.

Mastery

Solves compound percentage change problems and evaluates real-world financial situations critically.

Example task

An investment of £5000 earns 3% compound interest per year. Find the value after 4 years.

Model response: Value = 5000 × 1.03⁴ = 5000 × 1.12551 = £5627.54 (to nearest penny). The compound interest earned is £627.54. Simple interest would give 5000 × 0.03 × 4 = £600 — compound earns £27.54 more because interest earns interest.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Direct proportion

skill AI Direct

MA-KS3-C055

Understanding and solving problems involving direct proportion

Teaching guidance

Introduce through real-world contexts: currency exchange, recipe scaling, speed-distance-time. Use double number lines and ratio tables to organise proportional reasoning. Establish the unitary method: find the value for one unit, then scale to the required amount. Introduce the algebraic representation y = kx, where k is the constant of proportionality. Plot directly proportional relationships on a graph and note they always pass through the origin and are straight lines. Compare with examples that look similar but are not directly proportional.

Vocabulary: direct proportion, directly proportional, constant of proportionality, unitary method, ratio table, y = kx, origin, linear, scaling, rate
Common misconceptions

Pupils often assume any relationship between two variables is directly proportional. They may not check whether the graph passes through the origin, which is a requirement for direct proportion. Some pupils confuse direct proportion with a linear relationship that has a non-zero y-intercept (y = mx + c where c ≠ 0). The unitary method is sometimes applied where it is not valid.

Difficulty levels

Emerging

Recognises direct proportion in simple contexts: when one quantity doubles, the other doubles.

Example task

If 4 oranges cost £2, how much do 12 oranges cost?

Model response: 12 is 3 times 4, so the cost is 3 × £2 = £6.

Developing

Uses the unitary method to solve direct proportion problems with non-simple multipliers.

Example task

7 identical books weigh 3.5 kg. How much do 11 books weigh?

Model response: 1 book weighs 3.5 ÷ 7 = 0.5 kg. 11 books weigh 11 × 0.5 = 5.5 kg.

Secure

Solves direct proportion problems algebraically using y = kx and identifies direct proportion from tables and graphs.

Example task

y is directly proportional to x. When x = 6, y = 15. Find y when x = 10.

Model response: k = y/x = 15/6 = 2.5. So y = 2.5x. When x = 10: y = 25.

Mastery

Applies direct proportion in complex contexts including y ∝ x² and y ∝ √x, and distinguishes these from linear proportionality.

Example task

The energy E of a moving object is directly proportional to the square of its speed v. When v = 4, E = 32. Find E when v = 10.

Model response: E = kv². 32 = k(16), so k = 2. E = 2v². When v = 10: E = 2(100) = 200. Note: doubling speed quadruples energy — this is why speed limits matter for road safety.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Inverse proportion

skill AI Direct

MA-KS3-C056

Understanding and solving problems involving inverse proportion

Teaching guidance

Use practical contexts: if 2 workers take 12 hours to build a wall, 4 workers take 6 hours (as workers double, time halves). Contrast with direct proportion to highlight the difference: in direct proportion, both quantities increase together; in inverse proportion, as one increases the other decreases. Introduce the algebraic representation y = k/x and show the characteristic curve on a graph (a reciprocal curve). Use tables of values to check whether a relationship is inversely proportional by showing that the product xy remains constant.

Vocabulary: inverse proportion, inversely proportional, reciprocal, constant product, y = k/x, hyperbola, as one increases the other decreases, rate
Common misconceptions

Pupils often confuse inverse proportion with negative correlation or with simply decreasing values. Some pupils think inverse proportion means 'opposite' — that y = -kx is inverse proportion. The key diagnostic is whether the product xy is constant (inverse proportion) versus the ratio y/x being constant (direct proportion). Pupils may also struggle with the graphical representation, expecting a straight line.

Difficulty levels

Emerging

Understands that in some situations, when one quantity increases the other decreases — the basic idea of inverse proportion.

Example task

If 4 workers take 12 days to build a wall, will 8 workers take more or fewer days?

Model response: Fewer days — more workers means the job is done faster. 8 workers is double, so the time halves: 6 days.

Developing

Solves inverse proportion problems using the unitary method: find the total work units first.

Example task

3 machines take 8 hours to complete a job. How long would 6 machines take?

Model response: Total machine-hours = 3 × 8 = 24. With 6 machines: 24 ÷ 6 = 4 hours.

Secure

Solves inverse proportion problems algebraically using y = k/x and identifies inverse proportion from tables and graphs.

Example task

y is inversely proportional to x. When x = 5, y = 12. Find y when x = 8.

Model response: k = xy = 5 × 12 = 60. y = 60/x. When x = 8: y = 60/8 = 7.5.

Mastery

Applies inverse proportion in complex contexts including y ∝ 1/x², and compares direct and inverse proportion algebraically and graphically.

Example task

The intensity of light I is inversely proportional to the square of the distance d from the source. At d = 2 m, I = 100 units. Find I at d = 5 m.

Model response: I = k/d². 100 = k/4, so k = 400. At d = 5: I = 400/25 = 16 units. Moving from 2 m to 5 m (×2.5 distance) reduces intensity by 2.5² = 6.25 times: 100/6.25 = 16 ✓.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Compound units

skill AI Direct

MA-KS3-C057

Using compound units like speed, unit pricing and density in problem-solving

Teaching guidance

Introduce speed as the first compound unit: distance ÷ time. Use the formula triangle (distance, speed, time) to practise all three rearrangements. Progress to density (mass ÷ volume) and unit pricing (cost ÷ quantity). Emphasise units: speed in m/s or km/h, density in g/cm³ or kg/m³. Use real-world contexts: comparing prices per kilogram in a supermarket, calculating journey times. Practise converting between units of compound measures (e.g., km/h to m/s). Connect to ratio and proportion — compound units express rates.

Vocabulary: compound unit, speed, distance, time, density, mass, volume, unit price, rate, per, metres per second, kilometres per hour, grams per cubic centimetre
Common misconceptions

Pupils commonly confuse which quantities to divide when calculating compound measures — for example, calculating density as volume ÷ mass instead of mass ÷ volume. Unit conversions within compound measures cause additional errors. Some pupils cannot reconcile different units of speed (mixing up m/s and km/h). The idea that a compound unit combines two different measurements into one is conceptually challenging.

Difficulty levels

Emerging

Understands that speed = distance ÷ time and can calculate speed in simple cases.

Example task

A car travels 120 km in 2 hours. What is its speed?

Model response: Speed = 120 ÷ 2 = 60 km/h.

Developing

Uses compound units (speed, density, unit pricing) in straightforward calculations with unit conversions.

Example task

Which is better value: 500g of cereal for £2.40 or 750g for £3.30?

Model response: 500g: £2.40/500 = £0.48/100g. 750g: £3.30/750 = £0.44/100g. The 750g box is better value (cheaper per 100g).

Secure

Solves multi-step problems using compound units, including those requiring unit conversions and formula rearrangement.

Example task

A metal block has mass 540g and volume 200 cm³. Find its density. Could it be aluminium (density 2.7 g/cm³)?

Model response: Density = mass/volume = 540/200 = 2.7 g/cm³. Yes, it matches aluminium's density.

Mastery

Applies compound measures in complex real-world problems, interpreting graphs of compound measures and converting between systems.

Example task

A runner completes 5 km in 22 minutes and 30 seconds. Express this as (a) min/km (b) km/h (c) m/s.

Model response: (a) 22.5 min ÷ 5 = 4.5 min/km. (b) 5 km in 22.5 min = 5 ÷ (22.5/60) = 5 ÷ 0.375 = 13.33 km/h. (c) 5000 m ÷ 1350 s = 3.70 m/s (2 d.p.). Each unit tells a different story: pace (min/km) is useful for runners, km/h for comparing with traffic, m/s for physics.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Financial mathematics

content AI Direct

MA-KS3-C093

Applying mathematical knowledge to financial contexts including interest

Teaching guidance

Use real-world financial contexts: bank accounts, saving for a purchase, comparing deals, understanding bills and payslips. Teach simple interest using the formula I = PRT/100 and compare with compound interest conceptually. Include percentage increase and decrease in financial contexts: VAT, discounts, profit and loss. Practise 'best buy' problems comparing unit prices. Introduce budgeting activities where pupils must make financial decisions within constraints. Emphasise that financial mathematics is an application of percentage and ratio skills, not a separate topic.

Vocabulary: simple interest, principal, rate, time, profit, loss, discount, VAT, budget, income, expenditure, savings, unit price, best buy, percentage change
Common misconceptions

Pupils often confuse simple interest (calculated on the original amount) with compound interest (calculated on the accumulated amount). Some pupils add VAT by calculating the percentage and then forgetting to add it to the original price. Others struggle with reverse percentage problems in financial contexts. The concept of percentage profit being calculated on the cost price (not the selling price) is frequently misunderstood.

Difficulty levels

Emerging

Can solve simple money problems involving the four operations.

Example task

You buy 3 items at £4.50 each and pay with a £20 note. How much change do you get?

Model response: Cost = 3 × £4.50 = £13.50. Change = £20 - £13.50 = £6.50.

Developing

Solves financial problems involving percentages, such as discounts, VAT and simple profit/loss.

Example task

A shopkeeper buys goods for £60 and sells them for £78. What is the percentage profit?

Model response: Profit = £78 - £60 = £18. Percentage profit = (18/60) × 100 = 30%.

Secure

Solves problems involving simple and compound interest, understanding the difference between the two.

Example task

£2000 is invested at 4% simple interest. How much is the investment worth after 3 years?

Model response: Interest per year = 4% of £2000 = £80. Total interest over 3 years = £240. Value = £2000 + £240 = £2240.

Mastery

Solves complex financial problems including repeated percentage change, comparing financial products, and understanding the time value of money.

Example task

Bank A offers 3.5% compound interest. Bank B offers 3.8% simple interest. For a £10,000 deposit over 5 years, which is better?

Model response: Bank A (compound): 10000 × 1.035⁵ = 10000 × 1.18769 = £11,876.86. Bank B (simple): 10000 + 10000 × 0.038 × 5 = 10000 + 1900 = £11,900. Bank B is better for 5 years. However, compound overtakes simple eventually — at year 12: A = 10000 × 1.035¹² = £15,111 vs B = 10000 + 4560 = £14,560.

Delivery rationale

Secondary maths concept — abstract, procedural, and objectively assessable.

Additive vs multiplicative reasoning

process AI Facilitated

MA-KS3-C094

Interpreting when problems require additive, multiplicative or proportional reasoning

Teaching guidance

Present paired problems where the same surface structure masks different underlying structures: 'Tom has 3 more sweets than Jill' (additive) versus 'Tom has 3 times as many sweets as Jill' (multiplicative). Use bar models to make the structural difference visible. Teach pupils to ask: 'Am I comparing by adding/subtracting or by multiplying/dividing?' Proportional reasoning extends multiplicative reasoning to situations involving two variables: if one doubles, does the other double (direct proportion) or halve (inverse proportion)? Include problems that require identifying the type of reasoning before calculating.

Vocabulary: additive reasoning, multiplicative reasoning, proportional reasoning, ratio, scale factor, times as many, difference, product, proportion, structure, compare
Common misconceptions

The most fundamental misconception at KS3 is applying additive reasoning to proportional situations. For example: 'If 3 workers finish in 12 days, 6 workers will finish in 9 days' (subtracting 3) rather than 6 days (halving). The bar model is the most effective tool for diagnosing and correcting this error. Some pupils also apply proportional reasoning to additive situations, multiplying when they should add.

Difficulty levels

Emerging

Can identify whether a problem requires addition or multiplication, but does not yet distinguish additive from multiplicative reasoning explicitly.

Example task

Tom has 8 sweets. He gets 3 more. How many now? Tom has 8 sweets. He triples his collection. How many now?

Model response: First: 8 + 3 = 11 (additive — adding a fixed amount). Second: 8 × 3 = 24 (multiplicative — scaling by a factor).

Developing

Distinguishes between additive and multiplicative comparison, choosing the correct approach for proportion problems.

Example task

Recipe for 4 people uses 300g flour. How much for 6 people? Is this additive or multiplicative?

Model response: This is multiplicative: 6/4 = 1.5 times as many people, so 300 × 1.5 = 450g flour. If it were additive, we would add a fixed amount regardless of the number of people — that doesn't make sense for recipes.

Secure

Identifies the correct reasoning type (additive, multiplicative, or proportional) for a given problem and explains why.

Example task

Ava is 10 and her brother is 6. In 4 years, will the age difference or the age ratio be the same?

Model response: Difference now: 10-6=4. In 4 years: 14-10=4. The difference stays the same (additive relationship — ages increase by the same amount). Ratio now: 10/6 = 5/3. In 4 years: 14/10 = 7/5. The ratio changes. Ages have an additive relationship (constant difference), not a multiplicative one.

Mastery

Analyses complex situations requiring a combination of additive and multiplicative reasoning, and identifies which type applies at each step.

Example task

A pool is filled by two pipes. Pipe A fills it in 6 hours, Pipe B in 4 hours. How long to fill it together? What type of reasoning is needed?

Model response: This is a rates problem (multiplicative). Pipe A fills 1/6 per hour, Pipe B fills 1/4 per hour. Together: 1/6 + 1/4 = 2/12 + 3/12 = 5/12 per hour. Time = 12/5 = 2.4 hours = 2 hours 24 minutes. The addition of rates (1/6 + 1/4) is additive, but the rates themselves are multiplicative (fraction of pool per hour). This problem requires both types of reasoning working together.

Delivery rationale

Secondary maths process concept — problem-solving benefits from structured AI delivery with facilitator for extended reasoning.