Number - Addition, Subtraction, Multiplication and Division
KS2MA-Y6-D002
Performing mental calculations with large numbers and mixed operations; using formal written methods for long multiplication and long division; identifying common factors, common multiples and prime numbers; understanding and applying the order of operations; solving multi-step problems involving all four operations.
National Curriculum context
Year 6 completes the primary programme for written and mental calculation by introducing long division as the final formal written method and by embedding the order of operations (BODMAS/BIDMAS) so that pupils can work reliably with expressions involving brackets and multiple operations. Building on the short multiplication and division of Year 5 and the secure times-table knowledge established by Year 4, pupils now extend written methods to 4-digit dividends divided by 2-digit divisors, a significant cognitive step requiring strong place value understanding. The explicit teaching of common factors, common multiples, and the distinction between prime and composite numbers deepens pupils' number-theoretic understanding and supports later work in algebra and ratio. Multi-step problem-solving receives sustained emphasis in Year 6, reflecting the fact that national assessments require pupils to select and combine appropriate operations across increasingly complex contexts. Mental calculation strategies are refined and extended so that pupils can perform efficient approximate and exact calculations without reliance on written methods for straightforward cases.
6
Concepts
3
Clusters
4
Prerequisites
6
With difficulty levels
Lesson Clusters
Multiply and divide using formal long methods
introduction CuratedLong multiplication and long division are the two formal written method pinnacles of primary arithmetic. They represent the major Year 6 procedural target.
Apply order of operations and work with common factors, multiples and primes
practice CuratedOrder of operations (BIDMAS) and common factors/multiples/primes are the conceptual number theory targets of Year 6. C006 co-teaches with C029.
Develop mathematical fluency and apply problem-solving strategies
practice CuratedMathematical fluency with number and problem-solving strategies are cross-cutting process skills that permeate Year 6 mathematics. C029 is linked to C006; C031 represents the statutory problem-solving requirement.
Teaching Suggestions (1)
Study units and activities that deliver concepts in this domain.
Four Operations
Mathematics Worked Example SetPrerequisites
Concepts from other domains that pupils should know before this domain.
Concepts (6)
Long Multiplication
skill AI DirectMA-Y6-C004
Mastery of long multiplication means pupils can reliably multiply a 4-digit number by a 2-digit number using the formal long multiplication algorithm, understand why each partial product is placed in its correct column, and can check their answer using estimation. A fully secure pupil can also select appropriate methods — mental, informal, or formal — for different problems and can solve multi-step problems that require long multiplication as one step.
Teaching guidance
Ensure pupils have thoroughly understood short multiplication (Year 5) before introducing the two-row long multiplication format. Use place value understanding to explain why the second partial product row is shifted one place to the left (multiplying by tens). Grid multiplication provides an effective bridge between informal methods and the formal algorithm: show how the four cells of the grid correspond to the four partial products in long multiplication. Estimation should always precede formal calculation. Regular practice with varied digit configurations (including zeros within numbers) builds fluency.
Common misconceptions
The most common error in long multiplication is forgetting to shift the second row of partial products one place to the left when multiplying by the tens digit. Pupils also make errors with carrying, particularly when sums exceed 10 in multiple columns simultaneously. Some pupils misalign digits in the answer, especially when the number contains zeros. Estimation before calculating helps pupils identify unreasonable answers.
Difficulty levels
Multiplying a 3-digit number by a 2-digit number using the grid method as a bridge to the formal layout.
Example task
Use the grid method: 245 × 36.
Model response: 200×30=6000, 200×6=1200, 40×30=1200, 40×6=240, 5×30=150, 5×6=30. Total: 6000+1200+1200+240+150+30 = 8,820.
Using the formal long multiplication layout for 4-digit × 2-digit with correct alignment and the zero placeholder.
Example task
Use long multiplication: 3,456 × 28.
Model response: 3,456 × 8 = 27,648. 3,456 × 20 = 69,120. Total: 27,648 + 69,120 = 96,768.
Reliably computing any 4-digit × 2-digit multiplication, checking with estimation, and solving multi-step problems.
Example task
A factory makes 2,475 items per day for 24 days. How many items in total? Estimate first.
Model response: Estimate: 2,500 × 24 ≈ 2,500 × 25 = 62,500. Exact: 2,475 × 24 = 59,400.
CPA Stages
concrete
Using place value counters to model the two partial products in long multiplication, physically demonstrating why the tens row is shifted left
Transition: Child explains the place value reasoning behind the zero placeholder and transitions to the written method without counters
pictorial
Using the grid method alongside the formal long multiplication layout to show correspondence of partial products, then practising the compact method
Transition: Child completes long multiplication using the compact method independently, correctly managing carries across both rows
abstract
Performing long multiplication fluently for any 4-digit × 2-digit calculation, with estimation and checking, and applying within multi-step problems
Transition: Child completes any long multiplication fluently and applies it confidently within multi-step problems
Delivery rationale
Upper primary maths (Y6) — most pupils at pictorial/abstract stage. AI can deliver with virtual representations.
Long Division
skill AI DirectMA-Y6-C005
Mastery of long division means pupils can divide a 4-digit number by a 2-digit divisor using the formal long division algorithm and can correctly interpret the remainder — expressing it as a whole number remainder, a fraction, or a decimal — according to the context of the problem. A fully secure pupil understands each step of the algorithm (estimate, multiply, subtract, bring down) and can perform the procedure reliably with numbers that require regrouping.
Teaching guidance
Long division is one of the most cognitively demanding written methods in the primary curriculum and should be introduced only after pupils are completely secure with short division. Begin with divisors from the times tables (e.g., 13, 15, 25) before progressing to less familiar divisors. The 'chunk' method (subtracting known multiples) can serve as a bridge to the formal algorithm for pupils who struggle. Explicitly teach the four-step cycle: estimate how many times the divisor goes into the partial dividend, write the quotient digit, multiply and write the product below, subtract. Practise identifying from the context whether to express the remainder as r___, as a fraction, or as a decimal.
Common misconceptions
Pupils frequently lose track of place value during long division, producing quotient digits in the wrong columns. A common error is not bringing down the next digit when the partial dividend is smaller than the divisor (the quotient digit at that step should be zero, which is often omitted). Pupils also confuse when to express the remainder as a fraction (½ of a pizza) versus rounding up (number of buses needed) — always connect to the problem context.
Difficulty levels
Dividing a 3-digit number by a 2-digit divisor from the times tables (e.g. 13, 15, 25) using the chunking method as a bridge.
Example task
Use chunking: 375 ÷ 25.
Model response: 375 – 250 (10 × 25) = 125. 125 – 125 (5 × 25) = 0. Answer: 10 + 5 = 15.
Using the formal long division layout for 4-digit ÷ 2-digit, following the estimate-multiply-subtract-bring-down cycle.
Example task
Use long division: 4,368 ÷ 14.
Model response: 43 ÷ 14 = 3 (14×3=42, remainder 1). Bring down 6: 16 ÷ 14 = 1 (14×1=14, remainder 2). Bring down 8: 28 ÷ 14 = 2. Answer: 312.
Completing long division for 4-digit ÷ 2-digit and interpreting remainders as whole numbers, fractions or decimals according to context.
Example task
A 2,350 cm ribbon is cut into 16 equal pieces. How long is each piece? Give your answer as a decimal.
Model response: 2,350 ÷ 16 = 146 remainder 14. Continue: 140 ÷ 16 = 8 r12, 120 ÷ 16 = 7 r8, 80 ÷ 16 = 5. Answer: 146.875 cm.
CPA Stages
concrete
Using place value counters and sharing trays to model long division by a 2-digit divisor, building the 'estimate-multiply-subtract-bring down' cycle with physical grouping
Transition: Child follows the estimate-multiply-subtract-bring down cycle without counters, writing out the multiples of the divisor as a reference
pictorial
Recording long division using the formal layout on paper, with a table of divisor multiples alongside, and practising remainder interpretation
Transition: Child completes long division with any 2-digit divisor on paper, interpreting remainders as whole numbers, fractions or decimals as context requires
abstract
Performing long division fluently, selecting the remainder form appropriate to context, and applying within multi-step problems
Transition: Child completes any long division fluently, writes a zero in the quotient when needed, and selects the correct remainder interpretation
Delivery rationale
Upper primary maths (Y6) — most pupils at pictorial/abstract stage. AI can deliver with virtual representations.
Order of Operations
knowledge AI DirectMA-Y6-C006
Mastery of the order of operations means pupils understand and can apply the rule that brackets are evaluated first, followed by multiplication and division (from left to right), then addition and subtraction (from left to right), and that this is a convention that makes mathematical expressions unambiguous. A fully secure pupil can evaluate multi-step expressions correctly, insert brackets to make expressions equal a given value, and explain why the convention is necessary.
Teaching guidance
Introduce through concrete examples that demonstrate the need for an agreed convention: show that 3 + 4 × 5 can be evaluated as either 35 or 23 without a rule, then establish that mathematicians have agreed on the order of operations to avoid ambiguity. Use the acronym BODMAS (Brackets, Other, Division, Multiplication, Addition, Subtraction) or BIDMAS as a memory aid but emphasise understanding over rote application. Provide exercises where pupils must insert brackets to produce a given answer (e.g., make 3 + 4 × 5 equal 35 by inserting brackets). Connect to calculator use: demonstrate that most calculators apply the order of operations automatically.
Common misconceptions
The most prevalent misconception is evaluating left-to-right without applying the order of operations (treating all operations as having equal priority). Pupils also commonly neglect to evaluate the contents of brackets first when brackets are nested or when brackets appear later in the expression. Some pupils misremember BODMAS as meaning division always before multiplication, when in fact they have equal priority and should be evaluated left to right.
Difficulty levels
Evaluating expressions with brackets first, recognising that brackets override left-to-right order.
Example task
Work out (3 + 4) × 5.
Model response: (3 + 4) × 5 = 7 × 5 = 35.
Applying BODMAS/BIDMAS: evaluating multiplication and division before addition and subtraction.
Example task
Work out 12 + 8 × 3 – 4 ÷ 2.
Model response: 8 × 3 = 24. 4 ÷ 2 = 2. Then 12 + 24 – 2 = 34.
Evaluating multi-step expressions with brackets and mixed operations, and inserting brackets to make a given expression equal a target value.
Example task
Insert one pair of brackets to make this true: 6 + 2 × 5 – 1 = 14.
Model response: Without brackets: 6 + 2 × 5 – 1 = 6 + 10 – 1 = 15. Try 6 + 2 × (5 – 1) = 6 + 2 × 4 = 6 + 8 = 14. ✓
Placing brackets in different positions within the same expression to produce very different results, and explaining why the order of operations causes the difference.
Example task
Place brackets in 48 ÷ 2 × 3 + 1 to make it equal 96. Then place brackets differently to make it equal 6. Explain why the same numbers and operations give such different answers.
Model response: For 96: 48 ÷ 2 × (3 + 1) = 24 × 4 = 96. The ÷ and × are done left to right, so 48 ÷ 2 = 24 first, then 24 × 4 = 96. For 6: 48 ÷ (2 × (3 + 1)) = 48 ÷ (2 × 4) = 48 ÷ 8 = 6. The inner brackets force 3 + 1 = 4 first, then the outer brackets force 2 × 4 = 8 before the division. In the first expression we divide then multiply (making the result larger); in the second we multiply first then divide into a bigger number (making the result smaller).
CPA Stages
concrete
Using physical number cards and operation signs to build expressions, then rearranging with bracket cards to show how brackets change the order of calculation
Transition: Child evaluates expressions with mixed operations using BODMAS without cards, explaining which operation is calculated first and why
pictorial
Annotating expressions on paper to show the order of evaluation, inserting brackets to make expressions equal given values, and using tree diagrams to show operation priority
Transition: Child evaluates any expression correctly using BODMAS and inserts brackets to achieve target values without trial and error
abstract
Evaluating complex expressions mentally using BODMAS, creating expressions with brackets for given targets, and explaining why the convention is necessary
Transition: Child applies BODMAS fluently in any expression and explains the convention clearly
Delivery rationale
Upper primary maths (Y6) — most pupils at pictorial/abstract stage. AI can deliver with virtual representations.
Common Factors, Common Multiples and Primes
Keystone knowledge AI DirectMA-Y6-C007
Mastery means pupils can systematically identify all common factors of two numbers, list common multiples, identify the lowest common multiple and highest common factor, and use these skills to support fraction work (finding common denominators, simplifying fractions). A fully secure pupil knows that prime numbers have exactly two factors and can apply this understanding to determine whether any number up to 100 is prime, using divisibility rules as efficient tools.
Teaching guidance
Build on Year 5 work on factors, multiples and primes by introducing the terms 'common factor', 'common multiple', 'highest common factor' and 'lowest common multiple'. Use Venn diagrams to organise the factors or multiples of two numbers visually, identifying the overlapping region as the common factors/multiples. Connect explicitly to fraction simplification (divide numerator and denominator by their highest common factor) and finding common denominators (use the lowest common multiple of the two denominators). Divisibility rules (by 2, 3, 5, 7, 9, 10, 11) help pupils work efficiently without listing all factors.
Common misconceptions
Pupils often confuse factors and multiples, and further confuse highest common factor (a factor, smaller than or equal to the number) with lowest common multiple (a multiple, larger than or equal to the number). Some pupils include 1 as a prime number (it is not, as it has only one factor). When finding common factors, pupils often stop at the first common factor they find rather than the highest. Systematic listing of all factors of both numbers into a Venn diagram prevents most of these errors.
Difficulty levels
Finding all factors of a number up to 50 by systematic trial, and identifying whether it is prime.
Example task
Find all factors of 36. Is 36 prime?
Model response: Factors: 1, 2, 3, 4, 6, 9, 12, 18, 36. Not prime (more than 2 factors).
Finding common factors and common multiples of two numbers, identifying the HCF and LCM.
Example task
Find the HCF of 24 and 36. Find the LCM of 6 and 8.
Model response: Factors of 24: 1,2,3,4,6,8,12,24. Factors of 36: 1,2,3,4,6,9,12,18,36. Common: 1,2,3,4,6,12. HCF = 12. Multiples of 6: 6,12,18,24... Multiples of 8: 8,16,24... LCM = 24.
Using HCF to simplify fractions and LCM to find common denominators, and identifying primes up to 100 using divisibility tests.
Example task
Simplify 48/60 using the HCF. Is 91 prime? Explain how you checked.
Model response: HCF of 48 and 60: factors of 48 include 12, factors of 60 include 12. HCF = 12. 48/60 = 4/5. 91: not divisible by 2,3,5. 91 ÷ 7 = 13. So 91 = 7 × 13, not prime.
CPA Stages
concrete
Using counters on Venn diagram hoops to find factors and common factors of pairs of numbers, and Cuisenaire rods to find common multiples by laying out sequences
Transition: Child finds HCF and LCM systematically and tests primeness without physical materials
pictorial
Drawing Venn diagrams of factor sets, recording factor trees for prime factorisation, and using HCF/LCM to simplify fractions and find common denominators on paper
Transition: Child finds HCF and LCM efficiently on paper and applies them to fraction operations
abstract
Finding HCF, LCM and testing primeness mentally, and applying fluently in fraction simplification, common denominators and divisibility problems
Transition: Child applies HCF, LCM and prime factorisation fluently in any mathematical context
Delivery rationale
Upper primary maths (Y6) — most pupils at pictorial/abstract stage. AI can deliver with virtual representations.
Mathematical Fluency with Number
skill AI DirectMA-Y6-C029
Mastery of mathematical fluency at Year 6 means pupils can recall and apply number facts (multiplication tables, factor pairs, fraction-decimal-percentage equivalences, powers of 10) instantly and accurately, and can select and execute mental and written calculation strategies efficiently across all four operations with integers, decimals and fractions. A fully secure pupil does not need to derive facts from first principles during problem-solving but has automated them to the level required for their working memory to be free to focus on problem structure and reasoning.
Teaching guidance
Mathematical fluency is developed through regular, varied practice rather than single-topic drills. Use mixed-fact retrieval exercises, timed challenges (with the emphasis on accuracy as well as speed), and application of facts in problem-solving contexts where fluent recall enables higher-level thinking. Regularly revisit all four operations and their inverses, including in contexts involving large numbers, negative numbers and non-integer values. Distinguish fluency (doing the right thing quickly and accurately) from speed alone: a pupil who makes errors quickly is not fluent. Connect fluency to estimation: a fluent pupil can also rapidly assess the approximate size of an answer.
Common misconceptions
Pupils and teachers sometimes confuse fluency with speed, neglecting accuracy. Some pupils develop apparent fluency through pattern-matching without conceptual understanding, leading to errors when the surface features of a problem change. The most damaging gap is in multiplication fact recall: without secure times-table knowledge, all four operations (including division, fractions and percentages) are impeded at every stage.
Difficulty levels
Recalling multiplication facts to 12 × 12 and their related division facts with automaticity.
Example task
Answer as fast as you can: 7 × 8, 9 × 6, 132 ÷ 11.
Model response: 56, 54, 12.
Selecting and applying efficient mental and written strategies for calculations with integers, decimals and fractions.
Example task
Work out 0.6 × 7 mentally. Work out 3/5 of 45.
Model response: 0.6 × 7 = 4.2 (6 × 7 = 42, then divide by 10). 3/5 of 45: 45 ÷ 5 = 9, × 3 = 27.
Applying fluent number skills to multi-step problems, choosing the most efficient method for each step.
Example task
A shop sells pens at £0.35 each. How much for 24 pens? What change from £10?
Model response: 24 × £0.35 = 24 × 35p. 24 × 35 = 24 × 30 + 24 × 5 = 720 + 120 = 840p = £8.40. Change: £10 – £8.40 = £1.60.
CPA Stages
concrete
Using times table grids, fraction-decimal-percentage cards and place value equipment for rapid fact retrieval practice, building speed through concrete manipulation
Transition: Child recalls all times tables, key equivalences and number bonds without any reference materials, selecting efficient calculation strategies
pictorial
Completing timed mixed-fact retrieval exercises on paper, selecting mental vs written methods for different calculations, and recording strategy choices
Transition: Child demonstrates fluent fact recall and strategic method selection in timed exercises with high accuracy
abstract
Applying number fluency within complex problem-solving: rapid fact recall freeing working memory for higher-level reasoning
Transition: Child applies number facts instantly within multi-step problems, with working memory free for reasoning and problem structure
Delivery rationale
Upper primary maths (Y6) — most pupils at pictorial/abstract stage. AI can deliver with virtual representations.
Problem-Solving Strategies
process AI DirectMA-Y6-C031
Mastery of problem-solving at Year 6 means pupils can select and apply appropriate problem-solving strategies — including working systematically, drawing a diagram, looking for patterns, working backwards, trying simpler cases, and identifying the information needed — to solve unfamiliar multi-step problems in a range of contexts. A fully secure pupil approaches novel problems with confidence and persistence, checks their answers for reasonableness, and reflects on whether their method was efficient.
Teaching guidance
Teach problem-solving strategies explicitly and by name so that pupils can consciously select and apply them. Use rich problems from a variety of contexts, including problems with more than one valid approach. Encourage pupils to articulate their strategy before beginning and to evaluate their strategy after completing the solution. Collaborative problem-solving, in which pupils explain their approaches to each other, develops both mathematical communication and metacognitive awareness. Include problems that have no solution, problems with multiple solutions, and problems where the initial approach does not work and pupils must try a different strategy — this builds the resilience and flexibility that distinguish strong mathematical problem-solvers.
Common misconceptions
Pupils often attempt to apply a recently learned procedure to a new problem without first reading to understand what the problem is asking. A very common error is computing an answer without checking whether it is reasonable in context (e.g., a negative number of people, or a fraction of a journey taking more time than the whole journey). Some pupils give up quickly on problems that do not yield to their first approach, rather than trying a different strategy. Regular problem-solving with deliberate strategy discussion and reflection builds the persistence required.
Difficulty levels
Identifying what a word problem is asking and selecting the correct operation.
Example task
A pack has 8 biscuits. I need 50 biscuits. How many packs do I need? What operation will you use?
Model response: Division. 50 ÷ 8 = 6 remainder 2. I need 7 packs (round up because I need at least 50).
Solving two-step problems by identifying the steps needed, selecting methods and checking the answer is reasonable.
Example task
Cinema tickets cost £7.50. A family of 4 goes. They also buy 2 buckets of popcorn at £4.25 each. What is the total cost?
Model response: Tickets: 4 × £7.50 = £30. Popcorn: 2 × £4.25 = £8.50. Total: £30 + £8.50 = £38.50.
Solving multi-step problems involving mixed operations across different mathematical domains, with systematic working and checking.
Example task
A rectangular garden is 12 m by 8 m. A circular pond (radius 2 m) is in the middle. Fencing costs £15 per metre. Grass seed costs £3 per m². How much does it cost to fence the perimeter and seed the remaining garden (not the pond)?
Model response: Perimeter: 2(12+8) = 40 m. Fencing: 40 × £15 = £600. Garden area: 12 × 8 = 96 m². Pond area ≈ π × 2² ≈ 12.57 m². Grass area ≈ 96 – 12.57 = 83.43 m². Seed cost ≈ 83.43 × £3 = £250.29. Total ≈ £850.29.
Solving unfamiliar problems that require selecting and combining knowledge from multiple domains, reasoning about which information is relevant, and evaluating whether an exact or approximate answer is appropriate.
Example task
A school hall is 20 m long and 15 m wide. 240 children need to sit on the floor for assembly. Each child needs a space 60 cm × 60 cm. Will they all fit? If 30 more children arrive, the head teacher says 'Squeeze up — everyone take 50 cm × 50 cm.' Is this enough? Show all working.
Model response: Hall area: 20 × 15 = 300 m². Child space: 0.6 × 0.6 = 0.36 m². Max children: 300 ÷ 0.36 = 833. 240 < 833, so yes, easily. With 270 children at 0.5 × 0.5 = 0.25 m²: need 270 × 0.25 = 67.5 m². 67.5 < 300, so yes, plenty of room. But in practice, rows need aisles and a stage takes some space — so the real capacity is lower. An estimate of roughly half the hall being usable (150 m²) still gives 150 ÷ 0.25 = 600, which is more than 270.
CPA Stages
concrete
Using physical manipulatives to model problems: building with blocks, drawing diagrams with real objects, acting out scenarios, and working systematically with concrete materials
Transition: Child selects an appropriate strategy (draw a diagram, work systematically, try simpler cases, work backwards) and explains their choice
pictorial
Drawing diagrams (bar models, tables, number lines) to represent problems, recording systematic trials, and evaluating which strategy is most efficient
Transition: Child represents problems pictorially, selects efficient strategies, and verifies answers for reasonableness
abstract
Solving unfamiliar multi-step problems using named strategies, checking answers, and reflecting on strategy choice
Transition: Child approaches unfamiliar problems with confidence, articulates their strategy before starting, checks answers, and reflects on efficiency
Delivery rationale
Upper primary maths (Y6) — most pupils at pictorial/abstract stage. AI can deliver with virtual representations.