Science KS4 Y10Y11 Exemplar

Rates of Reaction: The Disappearing Cross

4 lessons

Subject
Science
Key Stage
KS4
Year group
Y10, Y11
Statutory reference
GCSE Chemistry: collision theory — reactions occur when particles collide with sufficient energy
Source document
Chemistry (KS4) - National Curriculum Programme of Study
Estimated duration
4 lessons
Status
Exemplar
Coverage: 8/13 expected capabilities surfaced
Curriculum anchorConcept modelDifferentiation dataThinking lensLesson structureSubject referencesPrior knowledge linksLearner scaffolding
Cross-curricular linksVocabulary definitionsSuccess criteriaAssessment alignmentAccess and inclusion

Enquiry questions

  • What is the effect of concentration on the rate of reaction between sodium thiosulfate and hydrochloric acid?

  • Concepts

    This study delivers 1 primary concept and 4 secondary concepts.

    Primary concept: Collision Theory and Reaction Rates (CH-KS4-C010)

    Type: Process | Teaching weight: 3/6

    Chemical reactions occur when reactant particles collide with sufficient energy (equal to or greater than the activation energy) and with correct orientation. Increasing concentration increases the frequency of collisions; increasing temperature increases both the frequency and energy of collisions; increasing surface area increases the frequency of collisions; a catalyst provides an alternative reaction pathway with lower activation energy.

    Teaching guidance: Required Practicals 6 and 7: sodium thiosulfate + acid (turbidity method) and marble chips + acid (gas volume method). Pupils should be able to measure and calculate mean rate of reaction from experimental data, and plot and interpret rate curves. Emphasise that catalysts are not consumed in reactions and do not change the overall energy change of the reaction — they only lower the activation energy. Biological catalysts (enzymes) should be connected to the Biology specification. Key vocabulary: collision theory, activation energy, frequency of collisions, concentration, pressure, temperature, surface area, catalyst, enzyme, rate of reaction, Maxwell-Boltzmann distribution Common misconceptions: Students say catalysts 'speed up reactions by giving energy to particles' — clarify that catalysts lower the activation energy by providing an alternative pathway. Students also think increasing temperature only increases collision frequency, forgetting the crucial effect on collision energy. Students confuse rate of reaction (speed) with yield (how much product is made).

    Differentiation

    LevelWhat success looks likeExample taskCommon errors

    EmergingKnows that reactions go faster when heated or when using smaller pieces, but cannot explain why using collision theory.Why does increasing the temperature increase the rate of a chemical reaction?Only mentioning increased collision frequency without mentioning increased collision energy; Saying particles 'collide harder' without linking this to activation energy
    DevelopingCan use collision theory to explain the effect of all five factors (concentration, temperature, surface area, pressure, catalyst) on reaction rate, and can calculate mean rate from experimental data.Calculate the mean rate of reaction if 60 cm³ of gas is collected in 120 seconds.Dividing time by volume instead of volume by time; Not including correct units in the answer
    SecureInterprets rate curves from experimental data, calculates rate at specific points from tangent gradients, and designs controlled experiments to investigate rate factors.A gas collection curve starts steep and then levels off. What does the gradient at any point represent? Why does the curve level off?Saying the reaction 'slows down because it runs out of energy' rather than correctly explaining that reactant concentration decreases; Not recognising that the final flat section means the reaction is complete, not just slow
    MasteryAnalyses rate data quantitatively, evaluates the effectiveness of different catalysts, and connects collision theory to industrial process optimisation.In the Haber process (N₂ + 3H₂ ⇌ 2NH₃), explain why an iron catalyst is used even though it does not change the equilibrium position.Saying the catalyst increases the yield of ammonia (it does not — it only increases the rate); Not connecting the catalyst's role to the economic viability of the industrial process

    Model response (Emerging): Increasing temperature gives the particles more kinetic energy. They move faster, so they collide more frequently AND with more energy. More collisions exceed the activation energy, so more collisions are successful and the reaction is faster.
    Model response (Developing): Mean rate = volume of gas / time = 60 / 120 = 0.5 cm³/s.
    Model response (Secure): The gradient at any point represents the rate of reaction at that instant. The initial steep gradient indicates a fast rate because reactant concentrations are highest. As reactants are consumed, their concentration decreases, so collisions become less frequent and the rate decreases (the gradient becomes less steep). The curve levels off when one reactant is completely used up — the reaction has finished and no more gas is produced.
    Model response (Mastery): The iron catalyst lowers the activation energy for both the forward and reverse reactions equally, so it does not change the equilibrium position or the yield of ammonia. Its value is in increasing the rate at which equilibrium is reached. Without a catalyst, the reaction would be so slow at the operating temperature (450°C) that the plant would be economically unviable. The catalyst allows the process to operate at a lower temperature than would otherwise be needed to achieve an acceptable rate, which has the added benefit of favouring the forward reaction (exothermic, so lower temperature shifts equilibrium to the right). This illustrates the industrial compromise: the catalyst enables a practical rate at a temperature that gives a reasonable yield (~15%), which is economically optimal even though it is not the thermodynamic optimum.

    Secondary concept: Atomic Structure and Subatomic Particles (CH-KS4-C001)

    Type: Knowledge | Teaching weight: 3/6

    An atom consists of a very small, dense, positively charged nucleus containing protons and neutrons, surrounded by electrons in shells at relatively large distances. Protons have a mass of 1 and charge of +1; neutrons have a mass of 1 and charge of 0; electrons have negligible mass and charge of -1. The atomic number (proton number) identifies the element; the mass number is the total of protons and neutrons.

    Differentiation

    LevelWhat success looks likeCommon errors

    EmergingCan name the three subatomic particles and state that atoms have a nucleus, but confuses their charges and relative masses or cannot use the periodic table to determine particle numbers.Stating that neutrons have a positive charge; Confusing atomic number (number of protons) with mass number (protons + neutrons)
    DevelopingCan use the periodic table to determine the number of protons, neutrons and electrons in an atom, and understands what isotopes are, but struggles with ion electron configurations.Thinking ions have different numbers of protons from the neutral atom; Subtracting atomic number from mass number the wrong way round
    SecureExplains the historical development of atomic models with reference to experimental evidence, calculates relative atomic masses from isotope data, and applies the nuclear model to explain ion formation.Describing the experiment without linking each observation to a specific conclusion about atomic structure; Confusing the Rutherford model (nuclear) with the Bohr model (electron shells)
    MasteryEvaluates the strengths and limitations of successive atomic models, calculates relative atomic masses from isotope abundance data, and explains why models in science are provisional and subject to revision.Simply averaging 35 and 37 to get 36 instead of using the weighted calculation; Not explaining why the RAM is an average rather than the mass of any individual atom

    Secondary concept: Moles and Stoichiometry (CH-KS4-C005)

    Type: Knowledge | Teaching weight: 5/6

    The mole is the unit of amount of substance; 1 mole of any substance contains 6.02 × 10²³ particles (Avogadro's number). The relative formula mass (Mr) numerically equals the mass in grams of 1 mole. Stoichiometry uses balanced equations to determine the molar ratios of reactants and products, allowing calculation of the mass of any reactant or product if the mass of another is known.

    Differentiation

    LevelWhat success looks likeCommon errors

    EmergingKnows that chemical equations must be balanced and that mass is conserved, but struggles with mole calculations and confuses mass with amount of substance.Forgetting to multiply the mass of oxygen by 3; Adding atomic numbers instead of atomic masses
    DevelopingCan calculate Mr, convert between mass and moles using moles = mass/Mr, and use molar ratios from balanced equations, but makes errors in multi-step calculations.Using the wrong molar ratio from the balanced equation; Dividing by Mr when they should multiply (or vice versa) in the final step
    SecurePerforms multi-step stoichiometry calculations confidently, including limiting reagent problems and concentration calculations, and can explain the significance of conservation of mass.Forgetting to convert cm³ to dm³ (divide by 1000); Using a 1:1 ratio instead of the correct 2:1 ratio from the balanced equation
    MasteryApplies stoichiometry to complex industrial and analytical contexts, evaluates sources of error in quantitative experiments, and uses the ideal gas equation for gas volume calculations.Confusing precision with accuracy — precise results can be inaccurate if there is systematic error; Not distinguishing between systematic errors (consistent bias) and random errors (scatter around the true value)

    Secondary concept: Exothermic and Endothermic Reactions (CH-KS4-C009)

    Type: Knowledge | Teaching weight: 3/6

    Chemical reactions involve breaking bonds in reactants (endothermic, requires energy) and forming bonds in products (exothermic, releases energy). If more energy is released forming bonds than is required breaking bonds, the overall reaction is exothermic and energy is released to the surroundings (temperature increases). If more energy is required to break bonds than is released forming bonds, the overall reaction is endothermic and energy is absorbed from the surroundings (temperature decreases).

    Differentiation

    LevelWhat success looks likeCommon errors

    EmergingCan give examples of exothermic and endothermic reactions and knows that exothermic reactions release heat, but confuses bond breaking (endothermic) with bond forming (exothermic).Saying 'breaking bonds releases energy' — breaking bonds always requires energy; Confusing exothermic (energy released, temperature increases) with endothermic (energy absorbed, temperature decreases)
    DevelopingCan draw energy level diagrams for exothermic and endothermic reactions, including activation energy, and understands that overall energy change depends on bond breaking versus bond forming.Drawing the products above the reactants for an exothermic reaction (products should be lower); Forgetting to include the activation energy hump — even exothermic reactions need energy input to start
    SecureCalculates overall energy changes using bond energy data, designs and interprets calorimetry experiments, and explains why catalysts lower activation energy but do not change the overall energy change.Subtracting bonds broken from bonds formed instead of the correct way round; Counting the wrong number of bonds (e.g., forgetting there are 4 C-H bonds in CH₄ and 4 O-H bonds in 2H₂O)
    MasteryEvaluates the accuracy and limitations of bond energy calculations, applies energy change concepts to real-world contexts, and explains Hess's law qualitatively.Not recognising that bond energies are averages and therefore approximate; Assuming that the calculated value should exactly match the experimental value

    Secondary concept: Reversible Reactions and Dynamic Equilibrium (CH-KS4-C011)

    Type: Knowledge | Teaching weight: 5/6

    Some chemical reactions are reversible: the products can react together to re-form the reactants. In a closed system, a dynamic equilibrium is established when the forward and reverse reactions occur at equal rates. The position of equilibrium can be changed by altering temperature, pressure or concentration. Le Chatelier's principle states that if a system at equilibrium is disturbed, it will shift to oppose the change.

    Differentiation

    LevelWhat success looks likeCommon errors

    EmergingKnows that some reactions can go backwards and that the Haber process makes ammonia, but cannot explain dynamic equilibrium or predict the effect of changing conditions.Thinking that ⇌ means the reaction goes forward first and then backward separately; Confusing reversible reactions with reactions that can be repeated
    DevelopingCan define dynamic equilibrium as a state where the forward and reverse reactions occur at equal rates, and can state Le Chatelier's principle, but struggles to apply it to specific examples.Confusing which direction is favoured — endothermic reactions are favoured by increasing temperature; Saying 'the reaction speeds up' without specifying the effect on equilibrium position
    SecureApplies Le Chatelier's principle to predict the effect of changes in temperature, pressure and concentration on equilibrium position, and evaluates industrial compromises.Not explaining the rate-yield trade-off (low temperature gives better yield but slower rate); Forgetting to mention that unreacted gases are recycled, which compensates for the low per-pass yield
    MasteryAnalyses equilibrium shifts quantitatively, evaluates the sustainability of industrial processes, and explains why catalysts do not affect equilibrium position.Accepting the claim that catalysts increase yield — this is one of the most common GCSE misconceptions; Not explaining the indirect benefit: catalysts allow lower operating temperatures, which can shift equilibrium


    Thinking lens: Patterns (primary)

    Key question: What patterns can I notice here, and what do they allow me to predict? Why this lens fits: Properties can be sorted and classified into patterns (metals conduct, insulators don't), allowing pupils to make predictions about unfamiliar materials. Question stems for KS4:
  • How would you formalise this pattern mathematically?
  • What are the limits of this pattern — where does it break down?
  • Could this pattern be an artefact of how the data was collected?
  • Does identifying the pattern tell us why it occurs?
  • Secondary lens: Structure and Function — Material properties link physical structure (molecular arrangement, surface texture) to functional behaviour (waterproofing, strength, flexibility) — the key question is always 'why does this material behave this way?'

    Session structure: Fair Test

    Fair Test

    The classic scientific enquiry: formulating a testable question, making a prediction based on scientific understanding, designing a method that controls variables, collecting and recording data systematically, analysing results, and drawing a conclusion linked back to the original hypothesis.

    questionhypothesismethoddata_collectionanalysisconclusion Assessment: Structured scientific report including question, hypothesis with reasoning, method with variables identified, results table/graph, and conclusion evaluating whether results support the hypothesis. Teacher note: Use the FAIR TEST template: expect pupils to derive a testable hypothesis from scientific theory and design a rigorous method with appropriate controls, precision, and sample size. Guide analysis using statistical techniques or mathematical modelling where appropriate. Demand critical evaluation of validity, reliability, accuracy, and the extent to which results support or refute the hypothesis. KS4 question stems:
  • How does your hypothesis follow from the underlying scientific theory?
  • How have you ensured sufficient precision, accuracy, and reliability in your method?
  • What statistical analysis supports your conclusion?
  • To what extent do your results support the hypothesis, and what are the limitations?

  • Variables

    Independent: concentration of sodium thiosulfate (diluted with water to maintain constant total volume) Dependent: time for the cross to disappear (seconds) Controlled: volume of hydrochloric acid, total volume of solution (thiosulfate + water), temperature, size and thickness of cross mark

    Equipment and safety

    Equipment:
  • sodium thiosulfate solution (40 g/dm³)
  • dilute hydrochloric acid (1M)
  • conical flasks
  • measuring cylinders (10ml, 25ml)
  • stopwatch
  • paper with printed cross (X)
  • safety goggles
  • fume cupboard or well-ventilated area
  • Safety notes: Wear safety goggles throughout. This reaction produces sulfur dioxide gas — work in a fume cupboard or ensure very good ventilation. Pupils with asthma should be positioned away from the reaction or observe from a distance. Sodium thiosulfate is an irritant. Hydrochloric acid is corrosive at higher concentrations — use dilute (1M). Wash any splashes to skin immediately. (Hazard level: standard)

    Expected outcome

    As the concentration of sodium thiosulfate increases, the time taken for the cross to disappear decreases because there are more reactant particles per unit volume, leading to more frequent successful collisions. Rate ∝ 1/time. Plotting rate (1/t) against concentration produces an approximately straight line through the origin, confirming a directly proportional relationship. Collision theory explains the result: higher concentration = more particles per unit volume = more frequent collisions = faster rate.

    Recording format: data table of concentration, time, and rate (1/time), scatter graph of rate (1/t) vs concentration, conclusion linking to collision theory

    Enquiry type

    Fair Test

    A controlled investigation where one variable is deliberately changed while all others are kept the same, to determine whether the changed variable has an effect on a measured outcome. The gold-standard enquiry type for causal questions in science.

    Question stems:
  • How does [independent variable] affect [dependent variable]?
  • Does changing [variable] make a difference to [outcome]?
  • What is the relationship between [variable A] and [variable B]?
  • Teacher scaffold:
  • What will you change? (independent variable)
  • What will you measure or observe? (dependent variable)
  • What will you keep the same? (controlled variables)
  • What do you predict will happen? Why?
  • Was your prediction correct? What does the evidence show?

  • Why this study matters

    The disappearing cross method is a classic GCSE practical because it produces clear, quantitative data with a simple visual endpoint. Calculating rate as 1/time and plotting rate against concentration develops the mathematical skills examiners test heavily. The practical provides concrete evidence for collision theory — the most important explanatory model in GCSE chemistry for understanding reaction kinetics.


    Pitfalls to avoid

  • Pupils forget to keep the total volume constant when diluting — if total volume changes, the depth of liquid above the cross changes, confounding the results
  • Subjective endpoint — different pupils may judge the cross to have 'disappeared' at different times. Discuss repeatability and compare results
  • Plotting time (not rate) against concentration gives a curve that is harder to interpret — always calculate 1/t
  • Sensitive content

  • Sulfur dioxide is produced — ensure asthmatic pupils are accommodated and the room is well ventilated

  • Vocabulary word mat

    TermMeaning

    activation energy
    atom
    atomic number
    avogadro's number
    balanced equation
    bond breaking
    bond energy
    bond forming
    calorimeter
    catalyst
    closed system
    collision theory
    concentration
    dynamic equilibrium
    electron
    electron shell
    endothermic
    energy level diagram
    enthalpy change
    enzyme
    equilibrium position
    excess reagent
    exothermic
    forward reaction
    frequency of collisions
    haber process
    ion
    isotope
    le chatelier's principle
    limiting reagent
    mass number
    maxwell-boltzmann distribution
    molar mass
    molar ratio
    mole
    neutron
    nucleus
    pressure
    proton
    rate of reaction
    relative atomic mass
    relative charge
    relative formula mass
    relative mass
    reverse reaction
    reversible reaction
    stoichiometry
    surface area
    temperature
    temperature change
    turbidity
    sulfur
    precipitate
    directly proportional

    Prior knowledge (retrieval plan)

    Pupils should already know the following from earlier units:

    Prior knowledge neededFor conceptDescription

    Covalent Bonding and Molecular StructuresExothermic and Endothermic ReactionsCovalent bonding occurs when atoms share pairs of electrons to achieve full outer shells. Simple ...
    Dalton atomic modelAtomic Structure and Subatomic ParticlesUnderstanding the simple Dalton model of atoms
    Atoms, elements, compoundsAtomic Structure and Subatomic ParticlesUnderstanding the differences between atoms, elements, and compounds
    Conservation of massMoles and StoichiometryUnderstanding that mass is conserved in changes of state and chemical reactions
    Chemical equationsMoles and StoichiometryAbility to represent chemical reactions using formulae and equations
    Types of reactionsReversible Reactions and Dynamic EquilibriumKnowledge of combustion, thermal decomposition, oxidation, and displacement reactions
    CatalystsCollision Theory and Reaction RatesUnderstanding what catalysts do in chemical reactions
    Energy in state changesExothermic and Endothermic ReactionsQualitative understanding of energy changes during changes of state
    Exothermic and endothermicReversible Reactions and Dynamic EquilibriumQualitative understanding of exothermic and endothermic chemical reactions


    Scaffolding and inclusion (Y10)

    GuidelineDetail

    Reading levelGCSE Year 1 Reader (Lexile 1000–1300)
    Text-to-speechAvailable
    VocabularyFull GCSE specialist vocabulary across all subjects. Exam-board-specific terminology expected. Command words must be used precisely and consistently. Subject-specific registers (scientific, literary-critical, historical, geographical) fully established.
    Scaffolding levelMinimal
    Hint tiers3 tiers
    Session length35–55 minutes
    Feedback toneExamination Coach
    Normalize struggleYes
    Example correct feedbackFull marks. You addressed all assessment objectives: identification (AO1), textual evidence (AO2), and analytical commentary on effect (AO3). Your use of subject terminology was precise.
    Example error feedbackThis response earns 3 of 8 marks. You identified the key feature (AO1 ✓) and quoted correctly (AO2 ✓), but your analysis describes what happens rather than explaining the effect on the reader (AO3 ✗). Additionally, you have not linked to the wider context (AO4 ✗). Revise to include both.


    Knowledge organiser

    Key terms:
  • rate of reaction
  • collision theory
  • activation energy
  • concentration
  • turbidity
  • sulfur
  • precipitate
  • directly proportional
  • Core facts (expected standard):
  • Collision Theory and Reaction Rates: Interprets rate curves from experimental data, calculates rate at specific points from tangent gradients, and designs controlled experiments to investigate rate factors.

  • Graph context

    Node type: ScienceEnquiry | Study ID: SE-KS4-007 Concept IDs:
  • CH-KS4-C010: Collision Theory and Reaction Rates (primary)
  • CH-KS4-C001: Atomic Structure and Subatomic Particles
  • CH-KS4-C005: Moles and Stoichiometry
  • CH-KS4-C009: Exothermic and Endothermic Reactions
  • CH-KS4-C011: Reversible Reactions and Dynamic Equilibrium
  • Cypher query:

    ``cypher

    MATCH (ts:ScienceEnquiry {enquiry_id: 'SE-KS4-007'})

    -[:DELIVERS_VIA]->(c:Concept)

    -[:HAS_DIFFICULTY_LEVEL]->(dl)

    RETURN c.name, dl.label, dl.description

    ``


    Generated from the UK Curriculum Knowledge Graph — zero LLM generation.